# Please solve and also explain the reason during the same... Let two waves from S1 and S2 interfere at P.   The two waves are given by where δ is the phase difference between two waves The resultant is given by (student should workout the required trignometry/algebra here )   Above equation shows that superposition of two sinusoidal waves with same frequency but with phase difference gives superposition of two sinusoidal waves of same frequency but different amplitudes. Where E is the resultant amplitude and φ is the resultant phase   By squaring and adding the above two equations we get since Intensity I proportional to E2, we can write If I1 = I2 = I0 and δ = 0, we get maximum Imax = 4I0 If I1 = I2 = I0 and δ = 2π, we get minimum Imin = 0 If I1 = I2 = I0 and δ  ranging from 0 to 2π, we get intensity between Imax   and Imin which is given by I = (1+cosδ)2I0 . When this intensity is averaged out for δ = 0 to 2π, we get average value 2I0   Hence the option (A) in the question is correct answer Answered by  | 4th Dec, 2017, 12:18: PM Concept Videos This video explains Young's double slit experiment for interference. This video establishes few mathematical expressions pertaining to interfere... This video provides expert tips and contains practice problems on interfere... Practice Test // \$(window).on('load', function(){ // \$(document).ready(function(){ if(showAds){ googletag.cmd.push(function() { /*googletag.defineSlot('/1039154/TopperLearning_WEB/TL_WEB_728x90_BTF', [[970, 90],[728, 90],[468, 60]], 'div-gpt-ad-1539848643692-article-detail-btf') .addService(googletag.pubads()).setCollapseEmptyDiv(true);*/ googletag.defineSlot('/1039154/TopperLearning_V1_WEB/TL_WEB_ROS_728x90_Bottom', [[970, 90], [728, 90]], 'div-gpt-ad-1585746040996-0').addService(googletag.pubads()).setCollapseEmptyDiv(true); }); } // }); // \$(window).on('load', function(){ // \$(document).ready(function(){ if(showAds){ googletag.cmd.push(function() { googletag.display('div-gpt-ad-1585746040996-0'); }); } // }); All Questions Ask Doubt coherent sources two coherent lights with of intensity 5 into 10 to power per to permit your each superimpose and produce the interference pattern on a screen at a point where the path difference between the wave is Lambda divided by 6 where Lambda is the wavelength of the wave find the first phase difference between wave second resultant intensity at the point We for equal wave intensities the intensity at a point is given by but where does the formula come from?? Question 15 kindly answer kindly provide answer pl In young double slit experiment, slit with ratio is 3:2 then find out the ratio of the maximum and minimum intensity of interference of light. How is phase difference related to path difference? In Young's double slit experiment, the distance between the slit is kept smaller than the wavelength of the light. What is the effect? Why is Interference pattern not detected when the two coherent sources are far apart? Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.

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