ICSE Class 10 Answered
please solve 178th question.
Asked by Kanwaranita10 | 04 Feb, 2020, 07:08: AM
Expert Answer
A boy is sitting at a distance of 1 m from one end.
Plank of see-saw is 4 m long.
The fulcrum of the see saw will be exactly at centre of plank i.e. 2 m
Thus, load arm is 2 - 1 = 1m
Thus,
Load =500 N
Effort = 400 N
Load arm x load = effort arm x effort
1 x 500 = EA x 400
Thus,
EA = 1.25 m
Thus, the distance at which Anu must sit from fulcrum is 1.25 m
By principle of moments, in equilibrium
Anticlockwise moment = clock wise moment
Answered by Shiwani Sawant | 04 Feb, 2020, 01:11: PM
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