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CBSE Class 11-science Answered

<div><img src="https://images.topperlearning.com/topper/tinymce/imagemanager/files/ea5241a35fb88fadf8cee88ec2fde7c95a1242ae428d96.67028802SBR9.jpg" alt="" />Please send the complete solution showing all the steps.</div>
Asked by sudhanshubhushanroy | 20 Nov, 2017, 08:20: AM
Expert Answer
begin mathsize 16px style generalizing comma considering space straight n space terms
sum from straight r equals 1 to straight n of fraction numerator straight C presuperscript straight n subscript left parenthesis 2 straight r minus 1 right parenthesis end subscript over denominator 2 straight r end fraction
equals fraction numerator sum from straight r equals 1 to straight n of open parentheses straight C presuperscript straight n subscript left parenthesis 2 straight r minus 1 right parenthesis end subscript close parentheses over denominator sum from straight r equals 1 to straight n of open parentheses 2 straight r close parentheses end fraction
equals fraction numerator 2 to the power of straight n minus 1 end exponent over denominator straight n left parenthesis straight n plus 1 right parenthesis end fraction...... sum space of space odd space terms space in space binomials end style
Answered by Arun | 29 Nov, 2017, 11:41: AM
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