Please send solution of 2 questions on chemical kinetics

Asked by sudhanshubhushanroy | 17th Nov, 2017, 09:41: AM

Expert Answer:

Energy space of space activation space equals fraction numerator Rln open parentheses begin display style straight k subscript 1 over straight k subscript 2 end style close parentheses over denominator open parentheses 1 over straight T subscript 2 minus 1 over straight T subscript 1 close parentheses end fraction


straight k subscript 1 equals straight K space space space straight K subscript 2 equals 2 straight K space

straight E subscript straight a space equals space space fraction numerator 8.314 cross times ln space open parentheses fraction numerator straight K over denominator 2 straight K end fraction close parentheses over denominator open parentheses begin display style 1 over 310 end style minus begin display style 1 over 300 end style close parentheses end fraction
space space space space space equals space space space open parentheses fraction numerator negative 5.7628 over denominator begin display style bevelled fraction numerator negative 10 over denominator 93000 end fraction end style end fraction close parentheses space
space space space space space equals space space fraction numerator negative 5.7628 over denominator 1.07526 cross times 10 to the power of negative 4 end exponent end fraction
space space space straight E subscript straight a space space space equals space space 53607.44 space Jmol to the power of negative 1 end exponent

Answered by Varsha | 17th Nov, 2017, 11:01: AM