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Asked by meghnananavati | 16th Apr, 2018, 06:05: PM

Expert Answer:

Let the distance between A and B is S
 
then we have v2 = u2+2×a×S;
 
where a is acceleration; then we have a = (v2-u2)/(2S)
 
let vm be the velocity at mid point; then we have vm2 = u2+2 [ (v2-u2)/(2S) ] (S/2) = ( u2 + v2 )/2 ;
 
hence vm = sqrt ( ( u2 + v2 )/2 )

Answered by Thiyagarajan K | 16th Apr, 2018, 10:27: PM

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