CBSE Class 12-science Answered
Please provide solution of this problem
Asked by | 02 Feb, 2010, 08:40: AM
Expert Answer
Assuming all the disintegrations are detected by the counter.
count rate = activity
dN/dt = -λe-λt N0
16000 = -λe-λt N0 .....(1)
After 4 hrs i.e. 240 min,
500 = -λe-λ(t+240) N0 ....(2)
Divide (2) by (1),
500/16000 = e+λt-λ(t+240)
500/16000 = e-240λ
ln (1/32) = -240λ
Use t1/2 = ln2/λ
ln (1/32) = -240(ln2/t1/2)
t1/2 = 240 ln2 / ln32
t1/2 = 240 ln2 / ln32 = 48 min.
Half life of the radioactive material is 48 min.
Regards,
Team,
TopperLearning.
Answered by | 02 Feb, 2010, 09:38: AM
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