CBSE Class 12-science Answered
Please provide solution of this problem
Asked by | 03 Feb, 2010, 04:51: PM
Expert Answer
Dear Student
Say the crossection of he wire =A
Length of P= L==> Length of Q= 1-L m
Resistance of initial P=r
After streaching the wire to length 2L resistance of wire R = 4r
==> resistance of Q wire = 4r,
Say resistivity of the material = s
resistance of Q wire = s(1-L)/A=4r ==> r=s(1-L)/(4A)------(1)
resistance of P wire = sL/A=r------------(2)
1,2=====> s(1-L)/(4A) =sL/A ==>(1-L)/4=L ==> 1-L=4L ==>L=1/5= 0.2 m ; 1-L = 0.8 m
Regads
Team Topperlearning
Answered by | 05 Feb, 2010, 06:06: PM
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