PLEASE HELP........................

pR² + pr² = 130p cm²

R² + r² = 130 cm²    (1)

R + r = 14 cm

r = 14 – R        

Substituting this in (1)

R² + (14 – R)² = 130

R² + 196 – 28R + R² = 130

R² – 14R + 33 = 0

(R - 11)(R - 3) = 0

Solving this quadratic equation we find,

R = 11 cm or 3 cm.

The radius of one circle is 11 cm and other is 3 cm.

 

Regards,

Team,

TopperLearning.