PLEASE HELP........................

Asked by mesourav | 5th Aug, 2009, 06:01: PM

Expert Answer:

pR2 + pr2 = 130p cm2

R2 + r2 = 130 cm2    (1)

R + r = 14 cm

r = 14 – R        

Substituting this in (1)

R2 + (14 – R)2 = 130

R2 + 196 – 28R + R2 = 130

R2 – 14R + 33 = 0

(R - 11)(R - 3) = 0

Solving this quadratic equation we find,

R = 11 cm or 3 cm.

The radius of one circle is 11 cm and other is 3 cm.

 

Regards,

Team,

TopperLearning.

Answered by  | 5th Aug, 2009, 06:43: PM

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