Please help me solving electrophilic aromatic substitution reaction's ques.

Ques. 11 of first pic.

Ques. 3 of 2nd pic.

Ques. 2 of third pic.

Please solve all three with detailed mechanism.

It won't take much time.

Please help.


Asked by jhajuhi19 | 29th Mar, 2020, 11:19: AM

Expert Answer:

Ans. 10
For ethyl benzoate, the aromatic ring has a -CO2CH2CH3 group attached which is an electron withdrawing group. Therefore the electrophilic aromatic substitution reaction will occur at the meta position giving 3-nitrophenyl ethanoate.
Ans. 11
A rate of Iodination of benzenes and hexadeuteriobenzene are different because C-D bond is stronger than C-H bond since mass of deuterium is twice that of hydrogen which gives strength in bonding.
Hence, K1>K2
Similarly as Ans.10, CN is an deactivating group hence the product obtained is metachlorocynobenzene.

Answered by Ramandeep | 29th Mar, 2020, 09:03: PM

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