Please help me find the solution

Asked by  | 24th Feb, 2010, 11:05: PM

Expert Answer:

let D,E,F be the mid pts of AB,BC,CA respectively.

so by mid pt thm we get

DF II BCthus, we get

angle ADF=angle ABC

angle A=angle A

So the triangles

ADF,ABC are similar.

 ratio of corr sides=1/2... as D is the mid pt.

 so

 ratio of areas=square of the ratio of corr sides=1/4

 

Answered by  | 25th Feb, 2010, 01:50: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.