Please help me find the solution

Asked by  | 24th Feb, 2010, 11:05: PM

Expert Answer:

let D,E,F be the mid pts of AB,BC,CA respectively.

so by mid pt thm we get

DF II BCthus, we get

angle ADF=angle ABC

angle A=angle A

So the triangles

ADF,ABC are similar.

 ratio of corr sides=1/2... as D is the mid pt.


 ratio of areas=square of the ratio of corr sides=1/4


Answered by  | 25th Feb, 2010, 01:50: PM

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