Please help me find the solution
Asked by | 24th Feb, 2010, 11:05: PM
let D,E,F be the mid pts of AB,BC,CA respectively.
so by mid pt thm we get
DF II BCthus, we get
angle ADF=angle ABC
angle A=angle A
So the triangles
ADF,ABC are similar.
ratio of corr sides=1/2... as D is the mid pt.
ratio of areas=square of the ratio of corr sides=1/4
Answered by | 25th Feb, 2010, 01:50: PM
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