CBSE Class 10 Answered
Please help me find the area of this figure?its very urgent.
Asked by | 08 Feb, 2012, 09:45: AM
Expert Answer
In the given figure let the arcs intersect at Point P
So , Join DP and CP
Now We can see that DP = CP = CD = 6
Since DCP is an equilateral triangle so its area = root(3)/4 * 6 * 6 = 9.root(3)
Now area of sector DCP = 60/360 * pie * 6 * 6 = 6pie
So are of segment between the arc from C to P and the chord CP = area of sectorDCP - area of traingle DCP = 6pie - 9root(3)
Now In sector BCD
Area of One of the shaded region = Area of sector BCD - { Triangle + two Segments}
= 6.17 cm2
Total area = 2 * 6.17 = 12.34 cm2
Answered by | 10 Feb, 2012, 10:41: AM
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