Please help me find the area of this figure?its very urgent.

Asked by  | 8th Feb, 2012, 09:45: AM

Expert Answer:

In the given figure let the arcs intersect at Point P

So , Join DP and CP

Now We can see that DP = CP = CD = 6

Since DCP is an equilateral triangle so its area = root(3)/4 * 6 * 6 = 9.root(3)

Now area of sector DCP = 60/360 * pie * 6 * 6 = 6pie

So are of segment between the arc from C to P and the chord CP = area of sectorDCP - area of traingle DCP = 6pie - 9root(3)

Now In sector BCD

Area of One of the shaded region = Area of sector BCD - { Triangle + two Segments}

= 6.17 cm2

Total area = 2 * 6.17 = 12.34 cm2

Answered by  | 10th Feb, 2012, 10:41: AM

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