Please guide me how to solve below TRIGNOMETRY problem

Asked by  | 9th Mar, 2008, 11:36: AM

Expert Answer:

  Consider  LHS =(CosA-SinA+1)/(CosA+SinA-1)

Multiplying and divide by (CosA+SinA+1)

we get (cos2A+1-sin2A+2cosA)/2sinA CosA

  (2Cos2A+2cos A)/2sinA CosA

= cosec A+cotA =RHS

Answered by  | 9th Mar, 2008, 02:21: PM

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