Please give the solution this question

Asked by anshuman.anshuman090 | 24th Jan, 2020, 06:48: PM

Expert Answer:

The question should be like this 
begin mathsize 16px style integral subscript 0 superscript straight pi over 2 end superscript space log open parentheses sin cubed xcos to the power of 4 straight x close parentheses dx equals fraction numerator negative 7 straight pi over denominator 2 end fraction log 2 end style
 
 
begin mathsize 16px style integral subscript 0 superscript straight pi over 2 end superscript log open parentheses sin cubed xcos to the power of 4 straight x close parentheses d straight x end style
begin mathsize 16px style integral subscript 0 superscript straight pi over 2 end superscript space open parentheses logsin cubed straight x plus logcos to the power of 4 straight x close parentheses dx end style
begin mathsize 16px style integral subscript 0 superscript straight pi over 2 end superscript space open parentheses 3 logsinx plus 4 logcosx close parentheses dx end style
Error converting from MathML to accessible text.
Error converting from MathML to accessible text.
Error converting from MathML to accessible text.
begin mathsize 16px style 7 cross times fraction numerator negative straight pi over denominator 2 end fraction log 2 equals fraction numerator negative 7 straight pi over denominator 2 end fraction log 2 end style

Answered by Sneha shidid | 28th Jan, 2020, 10:26: AM

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