please give the proof of relation= h'/h= -v/u

Asked by  | 20th Oct, 2012, 09:13: PM

Expert Answer:

from triangles ABP and A'B'P
AB/A'B' = BP/B'P
(-h)/h'= (-u)/(-v)              using sign conventions
hence
h/h' = - u/v

Answered by  | 21st Oct, 2012, 12:10: AM

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