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CBSE Class 12-science Answered

<div><img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=e96750c4f32ffed8d646dfa3c013ffac.png" alt="integral square root of sin to the power of negative 1 to the power of blank end exponent end root open parentheses x minus a close parentheses fraction numerator 1 over denominator square root of sin to the power of negative 1 end exponent end root left parenthesis x plus b right parenthesis end fraction" align="middle" />&nbsp;=&nbsp; ?</div> <div>&nbsp;</div> <div>PLEASE GIVE STEP BY STEP ANSWER ?</div>
Asked by modi72879 | 06 Oct, 2017, 09:02: AM
Expert Answer
Please share snapshot of the question. I think there is some error in the question.
Answered by Sneha shidid | 06 Oct, 2017, 11:14: AM
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