Please give  answer of the following

Asked by Balbir | 5th Jan, 2018, 11:39: AM

Expert Answer:


straight A space plus space straight B space space rightwards arrow space open parentheses straight A close parentheses subscript straight n space space plus space space straight B

As comma
straight P subscript straight m space space equals space space straight P to the power of 0 subscript straight A space straight X subscript straight A space end subscript space plus space space straight P to the power of 0 subscript straight B space straight X subscript straight B space space space space.......... left parenthesis 1 right parenthesis

straight P subscript straight m space space equals space 300 open parentheses fraction numerator straight a over denominator 12 plus straight a end fraction close parentheses plus 500 open parentheses fraction numerator 12 over denominator 12 plus straight a end fraction close parentheses

Here comma space after space 100 space min space apostrophe straight a apostrophe space mole space of space straight A space are space left space after space polymerisation

As comma

space straight K space equals fraction numerator space 2.303 over denominator straight t end fraction space log 10 over straight a

straight K space equals space fraction numerator space 2.303 over denominator 100 end fraction space log 10 over straight a space space space............. left parenthesis 2 right parenthesis
Solute space is space added space after space 100 space min space and space final space vapour space pressure space is space 400
space
space therefore space fraction numerator straight P subscript straight m minus 400 over denominator 400 end fraction space equals space fraction numerator 0.525 over denominator open parentheses straight a plus 12 close parentheses end fraction space space.......... left parenthesis 3 right parenthesis

Solving space eq space left parenthesis 1 right parenthesis space and space left parenthesis 3 right parenthesis

We space get space straight a space equals space 9.9

Now space putting space this space value space in space eq space left parenthesis 2 right parenthesis comma space
we space get

straight K space equals fraction numerator space 2.303 over denominator 100 end fraction space log fraction numerator 10 over denominator 9.9 end fraction

straight K space equals space 1 cross times 10 to the power of negative 4 end exponent space min to the power of negative 1 end exponent

Answered by Varsha | 5th Jan, 2018, 08:00: PM