CBSE Class 10 Answered
Please find the sum.
Asked by sunil_0010 | 01 Jul, 2009, 10:36: PM
Expert Answer
the sum of first six terms of an A.P. with a as the first term and d as the common diff, is
=6/2[2a+5d]
=3[2a+5d]
=42(given)
so
2a+5d=14..(i)
next,
10th term/30th term=1/3(given0
So,
(a+9d)/(a+29d)=1/3
i.e.
2a=2d
so
a=d
substituting in(i) we get,
7d=14
a=2
so
d=2
so first erm =2
11th term=a+10d=2+20=22
Answered by | 02 Jul, 2009, 09:25: AM
CBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:53: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by hanugraha | 30 May, 2010, 07:13: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 04:59: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by ROJAAPPA | 29 May, 2010, 12:58: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 29 May, 2010, 10:52: AM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by devanshmudgal | 28 May, 2010, 07:31: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:12: PM
ANSWERED BY EXPERTCBSE 10 - Maths
Asked by shobhitdc | 28 May, 2010, 01:08: PM
ANSWERED BY EXPERT
