CBSE Class 9 Answered
please explain
Asked by pcoolboy | 21 Dec, 2009, 08:00: PM
Expert Answer
The time required to attain maximum height,
t = u/g = 15/9.8 = 1.53 s
The time 1 second before reaching maximum height = 1.53 - 1 = 0.53
The distance travelled in the last second = distance travelled in 1.53 s - distance travelled in 0.53 s
= (ut1 - (1/2)gt12 )- (ut2 - (1/2)gt22)
= 15 - 0.5x9.8(1.532 - 0.532)
= 4.9 m
Regards,
Team,
TopperLearning.
Answered by | 21 Dec, 2009, 10:12: PM
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