PLEASE EXPLAIN STEP-BY-STEP:
Asked by | 13th Feb, 2009, 12:54: PM
standrad eqn of ellipse is X2/a2 + Y2 / b2 = 1 compairing with above eqn. we get a = 2 and b = 3
as b>a so ellipse has y axis as major axis and length of major axis is 2b = 6 and length of mionr axis is 2a = 4
eccentricity as we know a2 = b2 (1-e2) putting values of a and b we get e = 5 / 3
so focii are (0,be) and (0,-be) which is (0,5) and (0, -
5)
Answered by | 13th Feb, 2009, 07:13: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change