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CBSE Class 10 Answered

please explain in detail?
Asked by abinash.gupta003 | 22 Dec, 2017, 01:41: PM
answered-by-expert Expert Answer 
Upward velocity of ball w.r.t lift is u
let the upward acceleration and downward acceleration be a

resultant acceleration = -g-a = -(g +a)


Ball reached a height  h and comes back to the man so dispalcemnet would be zero 

h=ut1 +(1/2)at12

0 = ut1 -(1/2)(a + g)t12
ut1=(1/2)(a +g)t12
a+ g = 2u/t1


t1= 2u/(a+g)

similaralry for case when man is descending down 

t2=2u / (g-a)


This hint should be able to help to get the answer

Answered by Gajendra | 22 Dec, 2017, 07:10: PM
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