Please explain how to solve using Gay Lussac's law of combining volumes:
1)20ml. each of oxygen and hydrogen and 10 ml. of carbon monoxide are exploded in an enclosure .What will be the volume and composition of the mixture of the gases when they are cooled to room temperature.
2)100cc each of water gas and oxygen are ignited and the resultant mixture of gases cooled to room temperature.Calculate the composition of the resultant mixture.
Asked by manalip2505 | 26th Jan, 2019, 11:14: AM
Volume of O2 VO2 = 20 ml
Volume of H2 VH2 = 20 ml
Volume of CO VCO = 10 ml
Oxygen and hydrogen are exploded in an enclosure;
2H2 + O2 → 2H2O ......(1)
Oxygen and carbon monoxide are exploded in an enclosure;
2CO + O2 → 2CO2 ........(2)
From Eq (1)
2 V of H2 reacts with 1 V of the O2.
Therefore, 20 ml of H2 reacts with 10 ml of O2.
So, 20- 20 = 10 ml of O2 remains unreacted.
From Eq (2)
2 V of CO reacts with 1 vol of O2
Therefore, 10 ml of CO reacts with 5 ml of O2 and gives 10 ml of CO2
So, from 10 ml of O2 10-5 = 5 ml remains unreacted.
The total composition of the resulting mixture is 5 ml O2 and 10 ml CO2.
Answered by Varsha | 29th Jan, 2019, 12:35: PM
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