please explain how the bonding takes place of sulphur dioxide and carbon monooxide with figures
Asked by ppratim02 | 4th Jul, 2014, 07:31: PM
Sulphur has 6 electrons in its outer level, and the oxygen atoms between them contribute another 4 (1 for each bond). That gives 10 electrons in total 5 pairs. 4 pairs are needed for the bonds, leaving 1 lone pair. Each double bond uses 2 bond pairs and can be thought of as a single unit.
There are 2 double bond units and 1 lone pair, which will try to get as far apart as possible – taking up a trigonal planar arrangement.
Because the lone pair isn’t counted when you describe the shape, SO2 is described as bent or V-shaped.
Carbon monoxide can be thought of as having two ordinary covalent bonds between the carbon and the oxygen atoms plus a co-ordinate bond using a lone pair on the oxygen atom.
Answered by Prachi Sawant | 7th Jul, 2014, 12:43: PM
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