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please answer
Asked by pranavjain | 23 Jul, 2010, 10:35: PM
answered-by-expert Expert Answer
10l of water is, 0.01 m3 of water = 10 kg of water
Energy given by heater = 1.5 kW x time = 1500 W x time  = 1500 J/s x time = 1500 J/s x 30 min
= 1500 J/s x 900 s = 135 x 104 J
The same amount of heat is taken up by water, mCpΔT = 10 kg x 4200 J/kg C x ΔT =  135 x 104 J
ΔT = 32.14 C.
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TopperLearning.
Answered by | 23 Jul, 2010, 11:05: PM

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