CBSE Class 9 Answered
let the number be x.
when x is divided by 35 it leaves a rem of 7
x-7 is fully divisible by 35
x-7 is a multiple of 35
x-7 is a multiple of 56 and 91.
so we see that
x-7 is a common multiple of 35,56,91
since we want the smallest num so x-7 is the least common multiple of 35,56,91
so x-7=3640(since 3640 is the reqd l c m )
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