please answer

Asked by pranavjain | 1st May, 2010, 04:54: PM

Expert Answer:

let the number be x.

ATQ

when x is divided by 35 it leaves a rem of 7

i.e.

x-7 is fully divisible by 35

i.e.

x-7 is a multiple of 35

similarly

x-7 is a multiple of 56 and 91.

so we see that

x-7 is a common multiple of 35,56,91

since we want the smallest num so x-7 is the least common multiple of  35,56,91

so x-7=3640(since 3640 is the reqd l c m )

so

x=3647

Answered by  | 4th May, 2010, 04:44: PM

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