Asked by abhishek11 | 7th Feb, 2010, 07:15: PM
Let the number of rows be N and M be cars per row.
Total number of cars at any time t = NM
M+3 then N-1.
M-3 then N+2.
But the total number cars are fixed at that time in the parking place.
(M+3)(N-1) = NM
3N - M = 3 ...............(1)
(M-3)(N+2) = NM
2M - 3N = 6 ............(2)
Solving (1) and (2),
N=4, M = 9.
Total number of cars at that particular time = 36
Answered by | 8th Feb, 2010, 06:07: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number