CBSE Class 10 Answered
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Asked by abhishek11 | 07 Feb, 2010, 07:15: PM
Expert Answer
Let the number of rows be N and M be cars per row.
Total number of cars at any time t = NM
M+3 then N-1.
M-3 then N+2.
But the total number cars are fixed at that time in the parking place.
Hence,
(M+3)(N-1) = NM
3N - M = 3 ...............(1)
and
(M-3)(N+2) = NM
2M - 3N = 6 ............(2)
Solving (1) and (2),
N=4, M = 9.
Total number of cars at that particular time = 36
Regards,
Team,
TopperLearning.
Answered by | 08 Feb, 2010, 06:07: AM
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