CBSE Class 9 Answered
please answer
Asked by nmenghani | 13 Jan, 2010, 10:32: AM
Expert Answer
Let R, H be the radius and height of given cone and r, h be the radius and height of cut off cone.
and V, v be their respective volumes,
V = πR2H/3 and v = πr2h/3
v = V/27
πr2h/3 = πR2H/(3x27)
r2h = R2H/27 .............(1)
Let y be the height for a location to cut off cone.
y + h = H
and r/R = h/H
r = hR/H
Using these in (1),
h3R2/H2 = R2H/27
h3 = H3/27
h = H/3
y + h = H
y = H - h
= H - H/3
y =2H/3
Hence the cone is cut off at a height 2/3 of the total height from bottom.
Regards,
Team,
TopperLearning.
Answered by | 13 Jan, 2010, 10:53: AM
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