please answer

Let R, H be the radius and height of given cone and r, h be the radius and height of cut off cone.

and V, v be their respective volumes,

V = πR²H/3 and v = πr²h/3

v = V/27

πr²h/3 = πR²H/(3x27)

r²h = R²H/27 .............(1)

Let y be the height for a location to cut off cone.

y + h = H

and r/R = h/H

r = hR/H

Using these in (1),

h³R²/H² =  R²H/27

h³ = H³/27

h = H/3

y + h = H

y = H - h

= H - H/3

y =2H/3

Hence the cone is cut off at a height 2/3 of the total height from bottom.

Regards,

Team,

TopperLearning.