Please answer tis question.

Asked by dineshchem108 | 1st Mar, 2019, 10:29: PM

Expert Answer:

Gravitational force of attraction between Mars and Phobos balances the centripetal force of circular motion.
 
Let M be the mass of Mars, m be the mass of satellite, r is distance between Mars and Phobos and
 
T is the period of revolution
 
we have
 
begin mathsize 12px style G fraction numerator M space m over denominator r squared end fraction space equals space m v squared over r space equals space m space omega squared space r space space equals space m space fraction numerator 4 straight pi squared over denominator T squared end fraction space r
H e n c e space M space equals space 1 over G fraction numerator 4 straight pi squared over denominator T squared end fraction space r cubed space equals space fraction numerator 1 over denominator 6.674 cross times 10 to the power of negative 11 end exponent end fraction cross times fraction numerator 4 straight pi squared over denominator open parentheses 459 cross times 60 close parentheses squared end fraction cross times open parentheses 9.4 cross times 10 to the power of 6 close parentheses cubed space almost equal to space 6.5 cross times 10 to the power of 23 space k g end style

Answered by Thiyagarajan K | 2nd Mar, 2019, 12:07: AM

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