CBSE Class 10 Answered
PLEASE ANSWER THIS..........
Asked by 2joseph | 30 Jul, 2009, 07:05: AM
Expert Answer
from the given info we get that
AD/CD=DB/DA
In triangles
ADB and CDA,
AD/CD=DB/DA
angle ADB=angleCDA=90 each (given)
so
triangle ADB similar to triangle CDA (SAS rule)
so
DAB=DCA..corr angles of sim triangles are equal ...(i)
but
DAB+DBA=90 (as AD perpendicu.to BC)
so
DCA+DBA=90 from(i)
So in triangle ABC,
Angle C+angle B=90
So
angle A=90 (Angle.Sum Prop.)
Answered by | 30 Jul, 2009, 08:08: AM
CBSE 10 - Maths
Asked by s.sreeram | 11 Mar, 2010, 08:14: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:24: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:08: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:05: PM
ANSWERED BY EXPERT