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Asked by Prashant DIGHE | 09 Oct, 2019, 22:01: PM
answered-by-expert Expert Answer
when an object is floating on liquid, upthrust given by liquid is balanced by weight of the object
 
Since half of volume of hollow sphere is immersed, upthrust = (V/2) ρw g    ........................(1)
 
where V is full geometrical volume of sphere, ρw is density of water and g is acceleration due to gravity.
 
weight of the hollow sphere =  Vs ρs g   ................................(2)
 
where Vs is shell volume of sphere and ρs is density of material of hollow sphere.
 
By equating (1) and (2), we have, (V/2) ρw = Vs ρs or   ρs = (1/2) ( V / Vs ) ρw ........................(3)
 
Volume ration V/Vs = [ (4/3)π 83 ] / [ (4/3)π ( 83 - 63 ) ]  ≈ 1.73
 
Hence density of material of hollow sphere, ρs = (1/2)×1.73×1000 = 865 kg /m3
 
 
Answered by Thiyagarajan K | 10 Oct, 2019, 09:35: AM

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