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CBSE Class 12-science Answered

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Asked by alanpeter9611 | 12 Feb, 2019, 06:08: PM
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Bijective space is space one space minus space one space and space onto for space one minus one straight f left parenthesis straight x right parenthesis equals left parenthesis straight y right parenthesis fraction numerator straight x minus 2 over denominator straight x minus 3 end fraction equals fraction numerator straight y minus 2 over denominator straight y minus 3 end fraction cross space multiply space and space simplify 3 straight x minus 2 straight x equals 3 straight y minus 2 straight y straight x equals straight y so space one space minus space one now space for space onto comma space for space every space straight x element of straight A space there space should space be straight f open parentheses straight x close parentheses equals straight y fraction numerator straight x minus 2 over denominator straight x minus 3 end fraction equals straight y straight x minus 2 equals xy minus 3 straight y straight x equals fraction numerator 2 minus 3 straight y over denominator 1 minus straight y end fraction element of straight A...... straight y not equal to 1 thus space for space any space straight y element of straight B comma space there space exists space fraction numerator 2 minus 3 straight y over denominator 1 minus straight y end fraction element of straight A. straight f open parentheses fraction numerator 2 minus 3 straight y over denominator 1 minus straight y end fraction close parentheses equals fraction numerator space fraction numerator 2 minus 3 straight y over denominator 1 minus straight y end fraction minus 2 over denominator space fraction numerator 2 minus 3 straight y over denominator 1 minus straight y end fraction minus 3 end fraction equals straight y..... so space this space is space true straight f space is space onto so space straight f space is space bijective straight f to the power of negative 1 end exponent open parentheses straight x close parentheses equals fraction numerator 2 minus 3 straight x over denominator 1 minus straight x end fraction equals 4 straight x equals 2 straight f to the power of negative 1 end exponent open parentheses 7 close parentheses equals fraction numerator 2 minus 3 open parentheses 7 close parentheses over denominator 1 minus 7 end fraction equals 19 over 6
Answered by Arun | 13 Feb, 2019, 12:51: PM

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CBSE 12-science - Maths
2+2=?
Asked by surajkumar85440 | 23 Nov, 2021, 10:30: AM
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CBSE 12-science - Maths
In R - {-1}, there is a binary operation '*' defined by a*b = a+b - ab, for all a,b belongs to R - {-1}. Is R - {-1} group?
Asked by goswamineha2611 | 31 Aug, 2020, 06:32: PM
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CBSE 12-science - Maths
Please answer this question 
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Asked by alanpeter9611 | 12 Feb, 2019, 06:08: PM
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CBSE 12-science - Maths
 Consider the binary operation * on the set {1, 2, 3, 4, 5} defined by a*b=HCF of a andb. Write the operation table of the operation *. Is * commutative? Justify. Also, compute: (a) (2*3)*5 (b) (2*3)*(4*5). 
Asked by niharikapabba2605 | 12 Oct, 2018, 07:21: PM
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CBSE 12-science - Maths
 Show that the binary operation * on A = R – {-1} defined as a*b = a + b + ab for all a,b belongs to A is commutative and associative on A. also find the identity element of  * in A and prove that every element of A in invertible mention each and every formula and minute details
Asked by haroonrashidgkp | 07 Jun, 2018, 11:03: AM
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CBSE 12-science - Maths
Define binary operation * on a set X.
Asked by Topperlearning User | 25 Apr, 2016, 08:38: AM
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CBSE 12-science - Maths
A binary operation is defined by x * y = 2x – 3y. Find *(3, 2).
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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CBSE 12-science - Maths
A binary operation is defined by a * b = ab/2. Is the binary operation commutative?
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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CBSE 12-science - Maths
A binary operation defined by a * b = ab. Is the binary operation associative?
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
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CBSE 12-science - Maths
For the binary operation * defined by a * b = a + b + 1. Find the identity element for operation *.
Asked by Topperlearning User | 26 Apr, 2016, 11:58: AM
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