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Asked by Prashant DIGHE | 03 Mar, 2020, 10:00: PM

Expert Answer

Option (2) is correct.

Given:

For bulb A,

Volume, V_A = 100 ml

Pressure, =P_A

For Bulb B,

Volume, =V_B

Pressure, P_B =

40 over 100 straight P subscript straight A

Using Boyle's law,

P_AV_A = P_BV_B

P_A × 100 =

40 over 100 straight P subscript straight A

× V_B

V_B =

fraction numerator 100 over denominator 0.4 end fraction

V_B = 250 ml

Before opening stopcock, volume of gas in bulb B must be (250-100) = 150 ml

Answered by Varsha | 04 Mar, 2020, 09:47: AM

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