please answer this

Asked by Prashant DIGHE | 26th Feb, 2020, 10:01: PM

Expert Answer:

The correct answer is option C.
 
Isopropyl alcohol is heated with a suspension of bleaching powder(CaOCl2) with water. The products produced are trichloromethane and acetone.   
Reactions proceeds as follows:
 
bold Step bold space bold 1 bold colon
stack space space CaOCl subscript 2 space with Bleaching
space powder below plus space straight H subscript 2 straight O rightwards arrow with blank on top Ca left parenthesis OH right parenthesis subscript 2 space plus space Cl subscript 2

bold Step bold space bold 2 bold colon
Cl subscript 2 plus space straight H subscript 2 straight O rightwards arrow with blank on top 2 HCl space plus space left square bracket straight O right square bracket

stack left parenthesis CH subscript 3 right parenthesis 2 OH with 2 minus propanol below space plus space left square bracket straight O right square bracket space rightwards arrow with blank on top space left parenthesis stack CH subscript 3 right parenthesis subscript 2 CO with Acetone below space plus space 2 HCl

bold Step bold space bold 3 bold colon
space left parenthesis stack CH subscript 3 right parenthesis subscript 2 CO with Acetone below space plus space 3 Cl subscript 2 space rightwards arrow with blank on top space space stack CCl subscript 3 COCH subscript 3 with blank below space plus space HCl

stack 2 space CCl subscript 3 COCH subscript 3 with blank below space plus space Ca left parenthesis OH right parenthesis subscript 2 space rightwards arrow with blank on top space stack 2 CHCl subscript 3 with Chloroform below space plus space left parenthesis CH subscript 3 COO right parenthesis subscript 2 Ca

Answered by Ramandeep | 27th Feb, 2020, 11:37: AM

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