please answer this

Asked by Prashant DIGHE | 3rd Mar, 2020, 10:06: PM

Expert Answer:

Given:
 
For He,
 
V1= 200 ml
 
P1 = 0.66 atm
 
V2 = 400 ml
 
P2 = ?
 
By using Boyle's law,
 
P1V1 = P2V2 
 
0.66×200 = P2 × 400
 
P2 = 0.33 atm
 
For O2 
 
V1= 400 ml
 
P1 = 0.52 atm
 
V2 = 400 ml
 
P2 = ?
 
By using Boyle's law,
 
P1V1 = P2V2 
 
0.52×400 = P2 × 400
 
P2 = 0.52 atm
 
Partial pressure of He and O2 is 0.33 and 0.52 respectively.

Answered by Varsha | 4th Mar, 2020, 11:00: AM