please answer this

Asked by Prashant DIGHE | 25th Feb, 2020, 10:06: PM

Expert Answer:

The correct answer is option C ethanol.
 
Because chloroform test is given by methyl ketones/aldehydes, and only ethanol on oxidation will produced a acetaldehyde. The reactions proceeds as follows:
 
bold Step bold space bold 1 bold colon
stack space space CaOCl subscript 2 space with Bleaching
space powder below plus space straight H subscript 2 straight O rightwards arrow with blank on top Ca left parenthesis OH right parenthesis subscript 2 space plus space Cl subscript 2

bold Step bold space bold 2 bold colon
Cl subscript 2 plus space straight H subscript 2 straight O rightwards arrow with blank on top 2 HCl space plus space left square bracket straight O right square bracket

stack straight C subscript 2 straight H subscript 5 OH with Ethanol below space plus space left square bracket straight O right square bracket space rightwards arrow with blank on top space stack CH subscript 3 CHO with Acetaldehyde below space plus space CH subscript 2 straight O

bold Step bold space bold 3 bold colon
space CH subscript 3 CHO space plus space 3 Cl subscript 2 space rightwards arrow with blank on top space space stack CCl subscript 3 CHO with chloral below space plus space 3 HCl

stack 2 space CCl subscript 3 CHO with chloral below space plus space Ca left parenthesis OH right parenthesis subscript 2 space stack rightwards arrow with blank on top space stack 2 CHCl subscript 3 with Chloroform below space plus space left parenthesis HCOO right parenthesis subscript 2 Ca

Answered by Ramandeep | 26th Feb, 2020, 12:15: PM

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