CBSE Class 10 Answered
please answer these questions
Asked by prasutally | 26 May, 2019, 08:20: AM
Expert Answer
In the above figure,
O is the cerntre of a circle.
OA = 5 cm ..... radius of outer circle
AC = 8 cm .... chord of outer circle and tangent to the inner circle.
To find: OB = ? ..... radius of inner circle
OB is perpendicular to AC. .. (i) ( Tangent is perpendicular to radius at its point of contact)
We know that perpendicular from the centre of circle to the chord bisects the chord.
AB = 4 cm
In ΔOAB,
From (i)
By Pythagoras theorem, we get
OB2 = OA2 - AB2
= 52 - 42
= 25 - 16
= 9
→ OB = 3 cm
Therefore radius of the inner circle is 3cm.
Answered by Yasmeen Khan | 27 May, 2019, 10:43: AM
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