Please answer the question
Asked by
| 31st May, 2009,
12:52: PM
Dear Student
In the figure PS, QT, RB perpendicular bisectes the linesegments AB, BC ,AC respectively
and AS=SB=BT=TC and say it is equals to r
AS=SB=BT=TC=r ==> (1)
Here I am going to prove that BP=BQ=BR and PBQ=
QBR=
RBP=1200
PBQ = 180-30-30 = 120 ==>(1)
RBQ=90+30= 120 ==>(2)
PBR=90+30= 120 ==>(3)
Consider PSD
PB Cos 30= SB ==> PB= SB/cos30 =r/ ( 3 /2) = 2r /
3 ==>(4)
Similarly QB =2r/3 ==>(5)
First let us find RC and then BR
Consider RBC
RC cos30=BC=2r ==> RC= 2r/ (3/2) =4r/
3
BR=RC cos 60 = (4r/3) X (1/2) = 2r/
3 ==> (6)
Here I am going to prove that BP=BQ=BR=2r/3 and
PBQ=
QBR=
RBP=1200
This is a property of equilateral triangle
SO PQR is an equilateral Triangle
Regards
Team
Topper learning
Answered by
| 8th Jan, 2010,
01:19: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change