CBSE Class 9 Answered
Dear Student
In the figure PS, QT, RB perpendicular bisectes the linesegments AB, BC ,AC respectively
and AS=SB=BT=TC and say it is equals to r
AS=SB=BT=TC=r ==> (1)
Here I am going to prove that BP=BQ=BR and PBQ=QBR=RBP=1200
PBQ = 180-30-30 = 120 ==>(1)
RBQ=90+30= 120 ==>(2)
PBR=90+30= 120 ==>(3)
Consider PSD
PB Cos 30= SB ==> PB= SB/cos30 =r/ ( 3 /2) = 2r / 3 ==>(4)
Similarly QB =2r/3 ==>(5)
First let us find RC and then BR
Consider RBC
RC cos30=BC=2r ==> RC= 2r/ (3/2) =4r/3
BR=RC cos 60 = (4r/3) X (1/2) = 2r/3 ==> (6)
Here I am going to prove that BP=BQ=BR=2r/3 and PBQ=QBR=RBP=1200
This is a property of equilateral triangle
SO PQR is an equilateral Triangle
Regards
Team
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