PLEASE ANSWER FAST EXAM NEAR

Asked by SSHHII | 13th Nov, 2009, 10:51: PM

Expert Answer:

There are 52 thursdays in a non leap year.

so in a leap year the two extra days(366=364+2)

There are seven  possibilities for the extra day

i.e. the sample space isS={ mon,-tue, tue-wed, wed-thurs, thurs-Fri, Fri-sat..sat- sun,sun-mon} (7 possibilities)..n(S)=7

Out of which five cases are fav for  the event of having a sunday..n(E)=5

So the prob of there being 52 thursdays is

n(E)/n(s)= 5/7.

Answered by  | 16th Nov, 2009, 10:12: AM

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