Please answer as quickly as possible!

Asked by  | 15th Feb, 2010, 08:27: PM

Expert Answer:

If they are collinear, then the equation of line, from (a,0) and (0,b), in y = mx + c form, is,

y = (-b/a)x + a

and the third point must be on this line.

1 = -b/a + a

a = -b + a2

a + b = a2

Divide both sides by a2,

1/a + 1/b = 1




Answered by  | 16th Feb, 2010, 06:45: AM

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