CBSE Class 10 Answered
Please answer as quickly as possible!
Asked by | 15 Feb, 2010, 08:27: PM
Expert Answer
If they are collinear, then the equation of line, from (a,0) and (0,b), in y = mx + c form, is,
y = (-b/a)x + a
and the third point must be on this line.
1 = -b/a + a
a = -b + a2
a + b = a2
Divide both sides by a2,
1/a + 1/b = 1
Regards,
Team,
TopperLearning.
Answered by | 16 Feb, 2010, 06:45: AM
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