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Asked by anjanakurup728 | 04 Nov, 2019, 09:44: PM
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Given:
 
straight E subscript begin inline style bevelled Cl subscript 2 over Cl to the power of minus end style end subscript superscript 0 space equals space 1.36 space straight V straight E subscript begin inline style bevelled Cr to the power of 3 plus end exponent over Cr end style end subscript superscript 0 space equals space minus 0.74 space straight V straight E subscript begin inline style bevelled fraction numerator Cr subscript 2 straight O subscript 7 superscript 2 minus end superscript over denominator Cr to the power of 3 plus end exponent end fraction end style end subscript superscript 0 space equals space 1.33 space straight V straight E subscript begin inline style bevelled fraction numerator MnO subscript 4 superscript minus over denominator Mn to the power of 2 plus end exponent end fraction end style end subscript superscript 0 space equals space 1.51 space straight V
 
Reduction potential of Cr3+ has least reduction potention, -0.74 V.
 
Therefore Cr is the strongest reducing agent.
Answered by Varsha | 05 Nov, 2019, 08:52: AM
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