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Asked by HEMAPRIYA | 16th Sep, 2010, 11:50: PM

Expert Answer:

cosθ-sin3θ=cos2θSo cosθ-cos2θ=sin3θ2sin3θ2sinθ2=2sin3θ2cos3θ2 sinθ2=cos3θ2           use sin2θ =2sinθcosθ and cosC - cosDcos2-θ2=cos3θ2Hence 2-θ2=3θ2solving, θ =4">

Answered by  | 17th Sep, 2010, 10:25: PM

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