CBSE Class 10 Answered
Pl. answer this question
Asked by | 16 Feb, 2010, 05:36: PM
Expert Answer
a(x2+1) - x(a2+1) = 0
ax2 - (a2 + 1)x + a = 0
x = {(a2 + 1) ± 
[(a2 + 1)2-4a2]}/2a
= {(a2 + 1) ± [(a4 + 2a2+ 1 - 4a2]}/2a
= {(a2 + 1) ±[(a4 - 2a2+ 1]}/2a
= {(a2 + 1) ±[(a2 - 1]}/2a
= a and 1/a
Writing the quadratic equation, in standard roots form, i.e. x2- (α+β)x + αβ = 0
x2- (a + 1/a)x + 1 = 0
ax2 - (a2+1)x + a = 0
which is exactly identical to the given quadratic equation.
Regards,
Team,
TopperLearning.
Answered by | 16 Feb, 2010, 06:37: PM
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