Asked by | 30th Nov, 2009, 06:35: PM
(i) Vowels in the given word are I,E,E,I,A,E. We can permute them by placing in even places
6!/(2!3!) = 60 ways, we divide by 2! and 3! because I is repeated twice and E thrice.
For each of these ways we can permute N,T,R,M,D,T in 6!/2! = 360 ways.
Hence the total ways of arranging the letters, is 360x60 = 21600.
(ii) Since the other of vowels don't change, we can permute 6 letters in any of 12 places while the order of vowels is always fixed.
12P6 /2!= 12!/(2!6!) = 332640 ways
Answered by | 2nd Dec, 2009, 09:34: PM
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