permutation and combination

Asked by  | 17th Mar, 2009, 11:48: PM

Expert Answer:

There are 8 letters in the word EQUATION.

Out of these 5 are vowels and 3 are consonants

The extreme left place has to be filled by a consonant , this can be done in ways.

Thwe extreme right place has to be  filled by a consonant, this can be done in 3 ways.

The remaining 6 places can be filled by the remaining 6 letters( after selecting 2 letters for the exteme left and extremem right place respectively)in P(6,6)=6! ways.

So ,

 by the fundamental principal of counting the total number of ways as required in the question is

5*(6!)*3=15*(6!)

=15*720

=10800.

Pl send each question seperately.

Answered by  | 18th Mar, 2009, 10:16: PM

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