PERMUTATION AN COMBINATION
Asked by devendra.mittal | 26th Oct, 2009, 01:17: PM
Let's assume that we put only one ring in any one figner.
Then we can select 5 different rings from 8 and permute them.
Hence the number of permutations = 8P5 = 8!/3! = 4x5x6x7x8 = 840.
Answered by | 11th Nov, 2009, 04:27: PM
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