PERCENTAGE ABANDANCE

Asked by saniya mahmood | 15th Feb, 2014, 07:04: PM

Expert Answer:

Solution:

Average atomic mass = 16.2u

Mass of 168X = 16

Mass of 188X = 18

Average atomic mass = (mass of 168X) (percentage) + (mass of 188X) (percentage)

                                                                    100

Let the percentage of isotope 1 with atomic mass 16 be ‘x’

So the percentage of isotope II with atomic mass 18 would be (100 – x)

16.2 = 16x  + 18(100-x)

                       100

Or 1620 = 16x  + 1800 – 18x

 x = 90

Thus, percentage of isotope I (i.e. 168X ) = 90 %

Percentage of isotope II (i.e. 188X ) = 100 – 90 = 10 %

Answered by  | 17th Feb, 2014, 10:42: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.