CBSE Class 9 Answered
PERCENTAGE ABANDANCE
Asked by saniya mahmood | 15 Feb, 2014, 07:04: PM
Expert Answer
Solution:
Average atomic mass = 16.2u
Mass of 168X = 16
Mass of 188X = 18
Average atomic mass = (mass of 168X) (percentage) + (mass of 188X) (percentage)
100
Let the percentage of isotope 1 with atomic mass 16 be ‘x’
So the percentage of isotope II with atomic mass 18 would be (100 – x)
16.2 = 16x + 18(100-x)
100
Or 1620 = 16x + 1800 – 18x
x = 90
Thus, percentage of isotope I (i.e. 168X ) = 90 %
Percentage of isotope II (i.e. 188X ) = 100 – 90 = 10 %
Answered by | 17 Feb, 2014, 10:42: AM
Application Videos
Concept Videos
CBSE 9 - Chemistry
Asked by shivalaxmi0205 | 08 Mar, 2023, 07:47: PM
ANSWERED BY EXPERT
CBSE 9 - Chemistry
Asked by rekhachaturvedu422 | 01 Aug, 2022, 04:16: PM
ANSWERED BY EXPERT
CBSE 9 - Chemistry
Asked by pandeyabhishek1576 | 16 Feb, 2022, 01:24: PM
ANSWERED BY EXPERT
CBSE 9 - Chemistry
Asked by senniasamy | 10 Jan, 2022, 08:48: PM
ANSWERED BY EXPERT
CBSE 9 - Chemistry
Asked by nathdarshana | 20 Nov, 2020, 07:03: PM
ANSWERED BY EXPERT
CBSE 9 - Chemistry
Asked by archanakad | 25 Aug, 2020, 08:59: PM
ANSWERED BY EXPERT
CBSE 9 - Chemistry
Asked by namyairmalwar9803.5sdatl | 07 Jun, 2020, 01:47: PM
ANSWERED BY EXPERT
CBSE 9 - Chemistry
Asked by fathima1012006 | 31 May, 2020, 10:44: AM
ANSWERED BY EXPERT
CBSE 9 - Chemistry
Asked by gspublicschool | 27 Apr, 2020, 11:23: AM
ANSWERED BY EXPERT
CBSE 9 - Chemistry
Asked by Jaiwanthsiva | 15 Apr, 2020, 01:51: PM
ANSWERED BY EXPERT