Asked by | 26th Jan, 2010, 11:38: PM
Let the image coordinates be (x', y')
y' = x + 2 and y = x' + 2
y2 = 4x
(x' + 2)2 = 4(y' - 2)
x'2 + 2x' + 4 = 4y' - 8
4y = x2 + 2x + 12.
This will be the image of the given parabola.
Answered by | 27th Jan, 2010, 02:51: AM
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