ICSE Class 9 Answered
One year ago, a man was four times as old as his son. After 6 years, his age exceeds twice his son's age by 9 years. Find their present ages
Asked by Farahshaikh919 | 11 Oct, 2018, 06:37: PM
Expert Answer
Let,
the present age of a man = x years
the present age of son = y years
According to the conditions,
x - 1 = 4(y - 1)
x - 4y = -3 ...(1)
x + 6 = 2(y + 6) + 9
x - 2y = 15 ....(2)
Subtracting (2) from (1), we get
x = 33 and y = 9
Therefore,
present age of a man = 33 years
present age of son = 9 years
Answered by Yasmeen Khan | 11 Oct, 2018, 07:18: PM
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