One mole of oxalic acid is equivalent to how many moles of NaOH, can you please explain

Asked by SURYA NARAYANAN | 26th Nov, 2010, 12:00: AM

Expert Answer:

Dear Student
The neutralization reaction is:
H2C2O4 + 2NaOH --> Na2C2O4 + 2H2O
oxalic acid is a diprotic acid.
So, oxalic acid gives 2 H+ into the solution, so it will take double the NaOH to neutralize it
(2 oxalic acid : 1 NaOH).

We hope that clarifies your query.

Answered by  | 27th Nov, 2010, 10:18: AM

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