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one mole of an ideal gas expand from 10 l to 20 l at 25C . what will be the work done
Asked by ishika2004sharma12 | 31 Dec, 2022, 11:25: AM
Expert Answer
The work done for an isothermal process is given by:
Work done (W) = −nRT ln(V2/V1) = −1 × 8.314 × 298 × ln(20/10) = -8.314×298×0.693 = −1716.95 J
Answered by | 01 Jan, 2023, 10:51: AM
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