On types of functions
Asked by spuneet23 | 19th Jul, 2009, 05:51: PM
for a function to be one one
we must have
f(a) not equal to f(b), if a not equal tob.
i.e.[a] not equal to [b] if a not equal to b
so by defn of greates int fn we get that
if a not equal to b then f(a0 not equal to f(b)
so it's not one one.
for a function to be onto
we must have some element c from codomain R such that f(a)=c where a belongs to the domain R.
but if c is not an integer then f(a) can't be c for any a as the answer of the greates integer fn has to be an integer.
so we see that every element of R the codomain does not have a preimage in the domain R.
so by definition of onto functions f is not onto.
Answered by | 19th Jul, 2009, 09:12: PM
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